[xsl] <xsl:for-each> help

Subject: [xsl] <xsl:for-each> help
From: "Zoe" <zoe@xxxxxxxxxxxx>
Date: Wed, 1 May 2002 15:56:11 -0400
I want to display the specific service id="01"'s name. 
how can I approach this? The result will be 'My News'. 
does it have any condition that I can use? Thanks. 

<xsl:for-each select="dynamictree/category/service"....? >
<!-- serviceid =01, name="My News" -->

XML file: 
- <dynamictree version="1" statuscode="0" statusdesc="OK">
- <category id="1" name="Favorite">
- <service id="01" name="My News">
  <querykeyword id="7003" name="News USA" /> 
  <querykeyword id="7004" name="News Africa" /> 
- <service id="02" name="My Stocks">
  <querykeyword id="7001" name="Stock Quotes" /> 

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

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