Subject: Re: [xsl] <xsl:for-each> help From: "Zoe Peng" <zoe@xxxxxxxxxxxx> Date: Wed, 1 May 2002 18:49:39 -0400 |
c.. thanks. --Zoe > [Zoe Peng] > > > many thanks. > > I won't be able to use <xsl:if test...> cuz the xml document is > > generate on the fly and the key is coming from parameter. But, I got > > what I need. It outputs "My News". > > > > This is what I want: > > <xsl:for-each select='dynamictree/category[@id="1"]'> > > <xsl:for-each select='service[@id="01"]'> > > servicename: <xsl:value-of select="@name" /> > > </xsl:for-each> > > </xsl:for-each> > > Glad I could help. I don't think you need the double for-each, though, > depending on what else you do in them that you haven't explained. Just by > what you have shown, a single for-each would do what you need. You could use > > <xsl:for-each > select='dynamictree/category[@id="1"]/service[@id="01"]'> > > Depending on whether there would be more than one of them, you might not > even need to use any for-each at all, just the value-of. > > Cheers, > > Tom P > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] <xsl:for-each> help, Thomas B. Passin | Thread | [xsl] Complex Match Pattern, Dung, Ming-tzung |
RE: [xsl] Complex Match Pattern, Dung, Ming-tzung | Date | Re: [xsl] XSL manipulating two XMLs, J.Pietschmann |
Month |