Subject: [xsl] Parsing a List From: kenneth.howlin@xxxxxxxxxx Date: Tue, 21 May 2002 09:23:11 -0700 |
Hi Guys, I'm pretty new to XSL and have a problem which I hope you might be able to help me with. I have the following code <!--customer_listStart--> <xsl:template match="DATALIST"> <table cellpadding="5" cellspacing="0" border="0"> <tr> <td width="135"><u><font color="green">Company</font></u></td> <td width="330"><u><font color="green">Address </font></u></td> <td width="100"><u><font color="green">Phone </font></u></td> <td width="100"></td> </tr> <xsl:apply-templates select="customer"/> </table> </xsl:template> <xsl:template match="customer"> <tr> <td valign="top"><a><xsl:attribute name="href"> adminViewCompanyByID?companyid=<xsl:value-of select="id"/>&companyname =<xsl:value-of select="invoicename"/></xsl:attribute><xsl:value-of select=" invoicename"/></a></td> <td valign="top"><xsl:value-of select="invoiceaddress"/></td> <td valign="top"><xsl:value-of select="phone"/></td> </tr> </xsl:template> Simply, all this code does is displays all customers contained in the database. However my problem is that I have 1000s of customers in the database and as a result all these are returned in one huge list. My web page is therefore ridicously wrong. Does anyone know anyway of displaying say 50 Customers at a time with a 'next' and "previous" link to display the next or previous 50. Any help would be greatly appreciated. Thanks - ken Ken Howlin Application Developer LAURDE Limited Unit 1A Renmore Business Park 10 Kilcoole Industrial Estate Kilcoole County Wicklow Ireland mobile: 087 92 85 660 telephone: + 353 1 2878187 email: kenneth.howlin@xxxxxxxxxx web: www.laurde.com XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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