Subject: Re: [xsl] Parsing a List From: Joerg Heinicke <joerg.heinicke@xxxxxx> Date: Wed, 22 May 2002 15:12:11 +0200 |
Excellent Joreg......thanks a million.
Any idea how I can get the "next 50" and "previous 50" links to work.
Thanks again ken
> >
mail from Joerg Heinicke
Hello Kenneth,
you can pass parameters to the stylesheet. In your case for example the number of the first element to show in the list:
<xsl:param name="first" select="1"/> <xsl:param name="count" select="50"/>
> <xsl:template match="DATALIST"> > <table cellpadding="5" cellspacing="0" border="0"> > <tr> > <td width="135"><u><font color="green">Company</font></u></td> > <td width="330"><u><font color="green">Address </font></u></td> > <td width="100"><u><font color="green">Phone </font></u></td> > <td width="100"></td> > </tr> > <xsl:apply-templates select="customer"/>
changed to: <xsl:apply-templates select="customer[position() >= $first][position() <= $count]"/>
> </table> > </xsl:template>
<xsl:template match="customer">
<tr> <td valign="top"><a><xsl:attribute name="href"> adminViewCompanyByID?companyid=<xsl:value-of select="id"/>
&companyname
=<xsl:value-of select="invoicename"/></xsl:attribute><xsl:value-of select
="
invoicename"/></a></td> <td valign="top"><xsl:value-of select="invoiceaddress"/></td> <td valign="top"><xsl:value-of select="phone"/></td> </tr> </xsl:template>
Simply, all this code does is displays all customers contained in the database. However my problem is that I have 1000s of customers in the database and as a result all these are returned in one huge list. My web page is therefore ridicously wrong.
Does anyone know anyway of displaying say 50 Customers at a time with a 'next' and "previous" link to display the next or previous 50.
Any help would be greatly appreciated.
Thanks - ken
Regards,
Joerg
System Development VIRBUS AG Fon +49(0)341-979-7419 Fax +49(0)341-979-7409 joerg.heinicke@xxxxxxxxx www.virbus.de
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