RE: [xsl] Immediate help required (Perl and xsl)

["James Fuller" <james.fuller@xxxxxxxxxx>]

> Second in Perl and xsl:
> 1. I need to send a parameter from Perl script to xsl.
> This parameter is directory structure. How to do this?

depends on what you are using to transform the XSLT, what perl library ?

and certainly there will be documentation on using parameters >?

 
> 2. How do I access this parameter in my xsl file?
> Can someone give an example for this.

you use <xsl:param/>

> 
> Third in xsl:
> I'm generating a XML document from a xsl stylesheet. I
> have a variable like this:
> <xsl:variable name="doctype_string"
> select="concat('//DTDs V',$version,' //EN//')"/>
> So I concatinate this. Now I need to print this in the
> header of xml document using doctype-public attribute,
> thats like this:
> <xt:document href="{file}" type="xml"
> doctype-public="$doctype_string">


have you just done a simple test using 
<xsl:value-of select="$doctype_string"/>
to see if your variable is returning anything ?
and the correct syntaxt would be using the curly
brackets e.g. {$doctype_string} will return var in 
an attribute.

gl, jim fuller


> When I do this, I have $doctype_string printed in the
> header. So what is a method to print the concatinated
> string "doctype_string" in the doctype header.
> I have tried out doctype-public="{$doctype_string}"
> too but this is printed in the header
> {$doctype_string}
> 
> Thanks in advance
> Regards,
> Sri...
> 
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