Subject: [xsl] Re: Sorting on call-template value? From: "Dimitre Novatchev" <dnovatchev@xxxxxxxxx> Date: Sun, 13 Apr 2003 21:29:39 +0200 |
"Randy Oxentenko" <randy@xxxxxxxxxxxxx> wrote in message news:001301c301da$5eef5f70$7d2d0fcf@xxxxxxxxxxxxxxxxx > I am a novice with XSLT. My question is with respect to the child of > <xsl:for-each> that is <xsl:sort>. Is it possible to use a result returned > from <xsl:call-template> as the sort key? This would be possible in XSLT 2.0 using xsl:function For now you can use a generic sort template, which accepts a "compare" template as a parameter. See for example: http://www.biglist.com/lists/xsl-list/archives/200303/msg00007.html ===== Cheers, Dimitre Novatchev. http://fxsl.sourceforge.net/ -- the home of FXSL XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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