[xsl] Accessing node-sets by index with position()

Subject: [xsl] Accessing node-sets by index with position()
From: Ryan Sawatzky <rsawatzky@xxxxxxxxxxx>
Date: Tue, 23 Sep 2003 14:13:16 -0500
Hi everyone,

I am trying to iterate through a list of nodes in a node-set by index using the position() function, and I am running into some difficulties.

XML snippet -----


XSLT snippet -----
<!-- $set is the node-set containing the two <field> elements -->

<xsl:for-each select="$set">
   <xsl:text>Iteration #</xsl:text>
   <xsl:value-of select="position()"/>
   <xsl:text> is '</xsl:text>
   <xsl:value-of select="$set[position()]"/>

This gives the following output
Iteration #1 is 111
Iteration #2 is 111

It seems as though the position() function is working, but when I try to get at the 2nd node by index, it goes to the first node. If I replace $set[position()] with $set[2], I get the following...

Iteration #1 is 222
Iteration #2 is 222

So I know that I the second node in the node set is correct, but position() won't get me to it. Does anyone know how I can fix this problem? Any help is greatly appreciated.


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