Subject: Re: [xsl] Accessing node-sets by index with position() From: "G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx> Date: Tue, 23 Sep 2003 17:13:58 -0400 |
<xsl:for-each select="$set"> <xsl:text>Iteration #</xsl:text> <xsl:value-of select="position()"/> <xsl:text> is '</xsl:text> <xsl:value-of select="$set[position()]"/>
<xsl:text>' </xsl:text>
</xsl:for-each>
...
So I know that I the second node in the node set is correct, but position() won't get me to it. Does anyone know how I can fix this problem?
T:\ryan>type ryan.xml <info> <field>111</field> <field>222</field> </info>
T:\ryan>type ryan.xsl <?xml version="1.0" encoding="iso-8859-1"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:template match="/"> <xsl:variable name="set" select=".//field"/>
<xsl:for-each select="$set"> <xsl:text>Iteration #</xsl:text> <xsl:value-of select="position()"/> <xsl:text> is '</xsl:text> <xsl:variable name="for-each-position" select="position()"/> <xsl:value-of select="$set[$for-each-position]"/> <xsl:text>' </xsl:text> </xsl:for-each>
</xsl:stylesheet> T:\ryan>saxon ryan.xml ryan.xsl Iteration #1 is '111' Iteration #2 is '222'
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