Re: [xsl] Accessing node-sets by index with position()

Subject: Re: [xsl] Accessing node-sets by index with position()
From: "G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>
Date: Tue, 23 Sep 2003 17:13:58 -0400
At 2003-09-23 14:13 -0500, Ryan Sawatzky wrote:
<xsl:for-each select="$set">
   <xsl:text>Iteration #</xsl:text>
   <xsl:value-of select="position()"/>
   <xsl:text> is '</xsl:text>
   <xsl:value-of select="$set[position()]"/>

In the predicate, the position() function is being reevaluated against the set variable and does not reflect the position() within the for-each loop.

So I know that I the second node in the node set is correct, but position() won't get me to it. Does anyone know how I can fix this problem?

Use a variable to capture the for-each position and then address what you want using it ... an example is below.

I hope this helps.

.......... Ken

T:\ryan>type ryan.xml

T:\ryan>type ryan.xsl
<?xml version="1.0" encoding="iso-8859-1"?>
<xsl:stylesheet xmlns:xsl="";

<xsl:output method="text"/>

<xsl:template match="/">
  <xsl:variable name="set" select=".//field"/>

<xsl:for-each select="$set">
   <xsl:text>Iteration #</xsl:text>
   <xsl:value-of select="position()"/>
   <xsl:text> is '</xsl:text>
   <xsl:variable name="for-each-position" select="position()"/>
   <xsl:value-of select="$set[$for-each-position]"/>


T:\ryan>saxon ryan.xml ryan.xsl
Iteration #1 is '111'
Iteration #2 is '222'


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