[xsl] nodeset comparison

["Todd Kleine" <tkleine@xxxxxxxxxxxxx>]

I am trying to solve the following problem and am having difficulty because
I'm new to this.  Can anyone help?

If I have a nodeset (#1)

<menu>
  <item>
	<text>test</text>
      <param required='y'>contactid</param>
      <param>searchtype</param>
  </item>
</menu>


and another nodeset (#2)

<parameters>
	<searchtype>Boolean</searchtype>
	<anotherparam>testing</anotherparam>
</parameters>


how do I compare these two such that the test in an

<xsl:choose>
	<xsl:when test="">
	...
	

returns false because the required param contactid (from <param
required='y'>contactid</param> in nodeset #1) is not an element name within
nodeset #2?  If on the other hand the "required" attribute did not exist
then the result of the comparison would be true as a match for searchtype as
an element name was found.

Thanks in advance.


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