Subject: Re: [xsl] problem - generating XML schema via XSLT From: Christian Sell <christian.sell@xxxxxxxxxxxxx> Date: Fri, 03 Oct 2003 20:17:55 +0200 |
Namespace declarations in the source document are translated by the XML parser into namespace nodes, they are not treated by XSLT as attribute nodes. Therefore, a namespace declaration can never contain an attribute value template (because it isn't an attribute).
You need to produce in the result tree a namespace node whose name (=prefix) is "" and whose string value (=namespace URI) is "test". (It's very confusing that you chose to use the name "prefix" to refer to the namespace URI!
In XSLT 2.0 you can do this with
<xsl:namespace name=""><xsl:value-of select="@prefix"/></xsl:namespace>
In 1.0 there is no direct way of doing this. The nearest equivalent is:
<xsl:variable name="dummy"> <xsl:element name="e" namespace="{@prefix}"/> </xsl:variable>
<xsl:copy select="xx:node-set($dummy)/*/namespace::*[.=@prefix]"/>
This creates a dummy element in the required namespace, and then copies the required namespace node to the result tree.
thanks, christian
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