[xsl] Generating an Xpath expression dynamically

Subject: [xsl] Generating an Xpath expression dynamically
From: "Anderson, Rick A" <RA135334@xxxxxxxxxxxxxxxxxxxxxxx>
Date: Tue, 21 Oct 2003 12:03:17 -0400
> Hi,
> I am trying to use XSLT to transform a set of XML files, each type with
> its own set of nodes, into a legacy file format. It is best if the XSLT
> was generic. I've tried to reference a second XML file that contains the
> transformation rules. This second XML file contains the relative XPath
> expression for each element in the source XML file and the target location
> in the legacy file format. I get the relative XPath string from the second
> XML file into a parameter, but when I try to use that parameter in a XSLT
> value-of element, it outputs the relative XPath string rather than the
> contents of that node in the source XML file.
> Does anyone know how to output the contents of an element node in a source
> XML file using a XPath string read in from another XML file?
> Thanks.

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