Re: [xsl] Generating an Xpath expression dynamically

Subject: Re: [xsl] Generating an Xpath expression dynamically
From: Jeff Kenton <jkenton@xxxxxxxxxxxxx>
Date: Tue, 21 Oct 2003 12:32:58 -0400


You have two choices here:

Either use the evaluate() extension function that many processors provide, or use a two step process where the first step creates a second stylesheet that you then use (in a second step) to process the input data.

Anderson, Rick A wrote:
I am trying to use XSLT to transform a set of XML files, each type with
its own set of nodes, into a legacy file format. It is best if the XSLT
was generic. I've tried to reference a second XML file that contains the
transformation rules. This second XML file contains the relative XPath
expression for each element in the source XML file and the target location
in the legacy file format. I get the relative XPath string from the second
XML file into a parameter, but when I try to use that parameter in a XSLT
value-of element, it outputs the relative XPath string rather than the
contents of that node in the source XML file.

Does anyone know how to output the contents of an element node in a source
XML file using a XPath string read in from another XML file?

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