Re: [xsl] Generating an Xpath expression dynamically

[Jeff Kenton <jkenton@xxxxxxxxxxxxx>]

Rick,

You have two choices here:

Either use the evaluate() extension function that many processors provide, or use a two step process where the first step creates a second stylesheet that you then use (in a second step) to process the input data.


Anderson, Rick A wrote:
> > Hi,
> > I am trying to use XSLT to transform a set of XML files, each type with
> > its own set of nodes, into a legacy file format. It is best if the XSLT
> > was generic. I've tried to reference a second XML file that contains the
> > transformation rules. This second XML file contains the relative XPath
> > expression for each element in the source XML file and the target location
> > in the legacy file format. I get the relative XPath string from the second
> > XML file into a parameter, but when I try to use that parameter in a XSLT
> > value-of element, it outputs the relative XPath string rather than the
> > contents of that node in the source XML file.
> >
> > Does anyone know how to output the contents of an element node in a source
> > XML file using a XPath string read in from another XML file?
> > Thanks.
>
>
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