Subject: RE: [xsl] Xml to Xml From: "Michael Kay" <mhk@xxxxxxxxx> Date: Fri, 31 Oct 2003 13:13:42 -0000 |
Write an identity template rule that copies elements: <xsl:template match="*"> <xsl:copy> <xsl:copy-of select="@*"/> <xsl:apply-templates/> </xsl:copy> </xsl:template> And an empty template rule that skips the others: <xsl:template match="V|U"/> Michael Kay > -----Original Message----- > From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx > [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of > poppe chris > Sent: 31 October 2003 12:20 > To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] Xml to Xml > > > > > Hello i want to converse an xml doc to an other one but > leaving out some > elements, ive tried several ways but it just wont work, > > here's what the original xml looks like > <?xml version="1.0"?> > <Bitstream xml:base="../CONTENT/final.yuv" > xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="YUV" > xmlns:yuv="YUV" xsi:schemaLocation="YUV > file:/D:/school/DIA-BSDL-1%5B1%5D.1/DELIVERY_2003_08_13/BSDLSo urce/../CONTENT/SCHEMAS/YUV.xsd"> <Frame> <Y> <Ysample>0 811008</Ysample> </Y> <V> <Vsample>811008 405504</Vsample> </V> <U> <Usample>1216512 405504</Usample> </U> </Frame> <Frame> <Y> <Ysample>1622016 811008</Ysample> </Y> <V> <Vsample>2433024 405504</Vsample> </V> <U> <Usample>2838528 405504</Usample> </U> </Frame> </Bitstream> now i want the same but withouth the V and U elements and their children thus something like <Bitstream ...> <Frame> <Y> <Ysample>...</Ysample></Y> </Frame> ... </Bitstream> thanks in advance, Chris _________________________________________________________________ Volg Expeditie Robinson op de voet! http://entertainment.msn.be/tv/expeditierobinson/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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