[xsl] XPath problem: Checking if imidiately preceding sibling is of a certain kind

["Ragulf Pickaxe" <jawxml@xxxxxxxxxxx>]

Hi all,

What I want achieved is the following:

With the following XML:

<root>
 <X><A a="1"/><A a="1"/><A a="2"/>Some text</X>
 <X><A a="4"/>Some text<br/>
       <A a="5"/>More text<br/>
       <A a="7"/>Even more text</X>
</root>

I want to group the A nodes that are next to each other, but not those that 
are not next to each other, all the while keeping the structure of the 
original document.

In the XSL document, which has some template much like this

<xsl:template match="/">
 <xsl:apply-templates select="*"/>
</

I have tried the following:

<xsl:template match="A[1]">
<!-- This groups all the A elements in a given X element
This means that the second X gets the grouped too much -->
</

Or:

<xsl:template match="A">
<!-- This one does not group any of them -->
</


In the second implementation I have the tried a choose, when, otherwise to 
get the grouping.

What I want to achieve is (in pseudocode):

<xsl:choose>
 <xsl:when test="not('The preceding sibling is an A node')"/>
   <!-- Do something -->
 </
 <xsl:otherwise>
   <!-- At the moment do nothing -->
 </
</

I have tried to look at the name() function, but I don't think I understand 
it correctly
test="not(preceding-sibling::*[1]/name()='A'" goes totally wrong.

I think it must be really simple, but I can't get my mind to work, it seems.

Any help will be greatly appreciated.

If anyone has a different approach, I will be grateful, but please bear in 
mind this is but an example.

Regards,
Ragulf Pickaxe :)

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