[xsl] change a attribute with a link?

["Markus Hanel" <markus.hanel@xxxxxx>]

hello,
I want to list some informations of pers_datas of some nodes. The routine is
equal for the attribut "admin", "interviewees" and "interviewer" of this
nodes. My idear is to make 3 links, every link opens the same file and evaluates
with one of the attributes: admin, interviewees or interviewer. Therefore I
had to change the value of "attribute::type" of the xslt elements:
apply-templates and template. Is there a possibility to arange this? 

xml file
<node type="admin">
  <pers_data></pers_data>
    <node type="school">
      <node type="interviewees">
        <pers_data></pers_data>
        <pers_data></pers_data>
        <pers_data></pers_data>
      </node>
      <node type="department">
        <node type="interviewer">
          <pers_data></pers_data>
          <pers_data></pers_data>
          <pers_data></pers_data>
        </node>
        ...


xsl file
<xsl:stylesheet>
...
<p><a><xsl:attribute name="href">test.xml</xsl:attribute>evaluate the
admin</a></p>
<p><a><xsl:attribute name="href">test.xml</xsl:attribute>evaluate the
interviewees</a></p>
<p><a><xsl:attribute name="href">test.xml</xsl:attribute>evaluate the
interviewer</a></p>

...
<xsl:apply-templates select="descendant-or-self::node[attribute::type =
'admin']" />
....................................should change to [attribute::type =
'interviewees']
<xsl:template match="node[attribute::type = 'admin']">
...
</xsl:template>
</xsl:stylesheet>

Many thanks
markus