AW: [xsl] change a attribute with a link?

Subject: AW: [xsl] change a attribute with a link?
From: <christof.hoeke@xxxxxxx>
Date: Tue, 30 Mar 2004 10:30:52 +0200
do you want to open the link with a parameter which type of pers_data you want to show or is this all on one file?

in case of the parameter you need to provide information which environment you work in (servlet?)

if you want to put it all in one file you could do something like:

<xsl:template match="/">
	<!-- this is slow, better to select the proper nesting if possible -->
	<xsl:apply-templates select="//pers-data"/>
</xsl:template>

<xsl:template match="pers_data">
	<p>
		<!-- @ is the same as attribute:: but i think much neater cause it is shorter -->
		<a href="test.xml?param={parent::node/@type}">
			<xsl:value-of select="parent::node/@type"/>
		</a>
	</p>
</xsl:template>


is that what you were trying to do?
chris



> -----Urspr|ngliche Nachricht-----
> Von: Markus Hanel [mailto:markus.hanel@xxxxxx]
> Gesendet: Dienstag, 30. Mdrz 2004 10:21
> An: xsl mailinglist
> Betreff: [xsl] change a attribute with a link?
> 
> 
> hello,
> I want to list some informations of pers_datas of some nodes. 
> The routine is
> equal for the attribut "admin", "interviewees" and 
> "interviewer" of this
> nodes. My idear is to make 3 links, every link opens the same 
> file and evaluates
> with one of the attributes: admin, interviewees or 
> interviewer. Therefore I
> had to change the value of "attribute::type" of the xslt elements:
> apply-templates and template. Is there a possibility to arange this? 
> 
> xml file
> <node type="admin">
>   <pers_data></pers_data>
>     <node type="school">
>       <node type="interviewees">
>         <pers_data></pers_data>
>         <pers_data></pers_data>
>         <pers_data></pers_data>
>       </node>
>       <node type="department">
>         <node type="interviewer">
>           <pers_data></pers_data>
>           <pers_data></pers_data>
>           <pers_data></pers_data>
>         </node>
>         ...
> 
> 
> xsl file
> <xsl:stylesheet>
> ...
> <p><a><xsl:attribute name="href">test.xml</xsl:attribute>evaluate the
> admin</a></p>
> <p><a><xsl:attribute name="href">test.xml</xsl:attribute>evaluate the
> interviewees</a></p>
> <p><a><xsl:attribute name="href">test.xml</xsl:attribute>evaluate the
> interviewer</a></p>
> 
> ...
> <xsl:apply-templates 
> select="descendant-or-self::node[attribute::type =
> 'admin']" />
> ....................................should change to 
> [attribute::type =
> 'interviewees']
> <xsl:template match="node[attribute::type = 'admin']">
> ...
> </xsl:template>
> </xsl:stylesheet>
> 
> Many thanks
> markus

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