Subject: Re: [xsl] XSL Problem From: "M. David Peterson" <m.david@xxxxxxxxxx> Date: Wed, 11 Aug 2004 12:53:24 -0600 |
When I was looking at this question I stumbled onto something that is confusing me, I'm hoping someone here can enlighten me.
Given this xml:
<?xml version="1.0" encoding="UTF-8"?> <root> <one> <two in="1">2.1</two> <two in="1">2.2</two> <two in="1">2.3</two> </one> <one> <two in="2">2.1</two> <two in="2">2.2</two> <two in="2">2.3</two> </one> <one> <two in="3">2.1</two> <two in="3">2.2</two> <two in="3">2.3</two> </one> </root>
If I want to copy all of the "two" nodes with an "in" attribute I could do this: <xsl:copy-of select="/root/one/two[@in]"/>
But if I want to get the first "two" node with an "in" attribute, why can't I do this?: <xsl:copy-of select="/root/one/two[@in][1]"/>
As I read the XPath spec, it seems to be saying that the second predicate should be evaluated using the context list and proximity position of the node set generated by the completion of the first predicate. Both XALAN and Saxon seem to be treating the previous as equivalent to this: <xsl:copy-of select="/root/one/two[@in and position()=1]"/>
Am I reading this incorrectly?
http://www.w3.org/TR/xpath#section-Location-Steps "The initial node-set is filtered by the first predicate to generate a new node-set; this new node-set is then filtered using the second predicate, and so on." http://www.w3.org/TR/xpath#predicates "The proximity position of a member of a node-set with respect to an axis is defined to be the position of the node in the node-set ordered in document order if the axis is a forward axis and ordered in reverse document order if the axis is a reverse axis. The first position is 1."
Thanks, Josh
On Wed, 11 Aug 2004 08:34:30 +0100, Michael Kay <mhk@xxxxxxxxx> wrote:
You can select the first NatureInterestCd = LIEN, using the predicate
AdditionalInterestInfo[NatureInterestCD='LIEN'][1]
In XPath 2.0 you can then exclude this from your result set by using the "except" operator, and similarly for the other exclusions.
It's harder to do "A except B" in XPath 1.0: EXSLT offers a set:difference() extension function, or you can use logic based on generate-id() or on the formula
A[count(.|B) != count(B)]
Alternatively, you can use a predicate such as
AdditionalInterestInfo[not(NatureInterestCD='LIEN' and not(preceding-sibling::*[NatureInterestCD='LIEN']))]
Michael Kay
-----Original Message----- From: Dale Earnest [mailto:dale.earnest@xxxxxxxxxxxxxxxxxxxxxxx] Sent: 11 August 2004 01:01 To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] XSL Problem
I've run into a difficult xslt problem and I was hoping someone may have some insight.
I have an XML structure that looks like this (the '...'s represent nodes that aren't directly relevant to the question and are omitted):
<PersAutoInsurance> <PersVeh> ... <AdditionalInterest> <AdditionalInterestInfo> <NatureInterestCd>ADDIN</NatureInterestCd> </AdditionalInterestInfo> </AdditionalInterest> <AdditionalInterest> ... <AdditionalInterestInfo> <NatureInterestCd>LIEN</NatureInterestCd> </AdditionalInterestInfo> </AdditionalInterest> <AdditionalInterest> ... <AdditionalInterestInfo> <NatureInterestCd>LIEN</NatureInterestCd> </AdditionalInterestInfo> </AdditionalInterest> </PersVeh> <PersVeh> <AdditionalInterest> ... <AdditionalInterestInfo> <NatureInterestCd>ADDIN</NatureInterestCd> </AdditionalInterestInfo> </AdditionalInterest> <AdditionalInterest> ... <AdditionalInterestInfo> <NatureInterestCd>LIEN</NatureInterestCd> </AdditionalInterestInfo> </AdditionalInterest> <AdditionalInterest> ... <AdditionalInterestInfo> <NatureInterestCd>AIL</NatureInterestCd> </AdditionalInterestInfo> </AdditionalInterest> </PersVeh> </PersAutoInsurance>
What I'm trying to do is select NatureInterestCd's based on the following criteria: 1) I cannot accept the first NatureInterestCd = LIEN for each vehicle (but may accept any subsequent for processing) 2) I cannot accept the first NatureInterestCd = AIL for each vehicle (but may accept any subsequent for processing) 2) I can accept any other node
I attempted to use this type of statement to get the nodes and loop over them: <xsl:for-each select="PersAutoInsurance/PersVeh/AdditionalInterest/Additiona lInterestInfo[not(NatureInterestCd = 'LIEN') and not(NatureInterestCd = 'AIL')]">
But that eliminates all nodes, not simply the first. I tried adding in a position() qualifier, but that ended up only checking the first node in the whole node-set selected.
I tried generate-id(PersAutoInsurance/PersVeh[1]/AdditionalInterest/Ad
ditionalInterestInfo[NatureInterestCd = 'LIEN'][1]) as that XPATH returns the LIEN I don't > want (I had to use it in another part of the xsl), but the ID
it generated wasn't the same as the ID that was being generated when I looped over the all the NatureInterestCd's, so I couldn't eliminate the node based on that.
I'm nearing my wits end on this problem and I was hoping that someone could give some insight into this problem.
Dale Earnest
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