Re: [xsl] Need exactly 23 rows of output before next page

["J.Pietschmann" <j3322ptm@xxxxxxxx>]

Clay Leeds wrote:
> I am re-creating a medical form which outputs exactly 23 rows per page 
> (i.e., if there are 3 rows of data, 23 nodes are output; if there are 24 
> rows of data, 46 nodes are output, w page one having 23 rows of data, 
> and page 2 having one row of data filled/22 rows empty, etc.).

Uhh, requirements straight out of hell...
You can compute the number of rows necessary to make the total number
a multiple of 26 using the mod operator, and fill the missing rows
using the wendell-piez-method or a recursive template:

<xsl:for-each select="DETAILLINE">
  <fo:table-row height=".8cm" border=".5pt solid {$varColor}"
        border-collapse="collapse" line-height="22pt">
    <fo:table-cell text-align="center" border-bottom=".5pt solid 
{$varColor}">
      <fo:block>
        <xsl:value-of select="DOSFROM/MM"/>
      </fo:block>
    </fo:table-cell>
..
  </fo:table-row>
</xsl:for-each>
<xsl:variable name="detail-count" select="count(DETAILLINE)"/>
<xsl:if test="($detail-count mod 23) != 0">
  <xsl:for-each select="//node()[position() <
   (24 - ($detail-count mod 23))]">
   ... add empty rows ...
  </xsl:for-each>
</xsl:if>

There should be multiple alternative, possibly more elegant
and/or correct formulations of the solution. If performance
is bad, switch to a recursive template (the XSLT FAQ has it
all).

J.Pietschmann