Re: [xsl] collapsing number ranges

[J-P S <jps@xxxxxxxxxxxxxxxxxxxx>]

On Fri, 27 Aug 2004, Jeni Tennison wrote:

) > 7777-7778 => 7777-78
)
) Taking a guess at the algorithm, what about:
)
)   <xsl:value-of select="@begin" />
)   <xsl:text>-</xsl:text>
)   <xsl:choose>

Gah! Of course! xsl:choose, but with recursion. I'm always averse to
recursive template calls, but I think the below will work for the general
case. Call this template with your start and end numbers, and "0" for the
digit parameter (or "1" or "2" if you *know* the first one or two digits
will always be the same, to speed things up):

	<xsl:template name="number">

	  <xsl:param name="start" />
	  <xsl:param name="end"/>
	  <xsl:param name="digits"/>

	  <xsl:choose>

	    <!-- If strings are the same for first $digit digits, call
		self with $digit+1 and test again -->
	    <xsl:when test="substring($start,1,$digits) =
			substring($end,1,$digits)">
	      <xsl:call-template name="number">
	        <xsl:with-param name="start" select="$start"/>
	        <xsl:with-param name="end" select="$end"/>
	        <xsl:with-param name="digits" select="$digits+1"/>
	      </xsl:call-template>
	    </xsl:when>

	    <!-- If strings aren't the same, then print $start,
		followed by a dash, followed by the tail end of $end -->
	    <xsl:otherwise>
	      <xsl:value-of select="concat($start,'-',
			substring($end,$digits,string-length($end)))"/>
	    </xsl:otherwise>

	  </xsl:choose>

	</xsl:template>

Let me know how you get on!

Cheers,
J-P
-- 
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