RE: [xsl] a question

[cknell@xxxxxxxxxx]

The precise form of the XPath depends on the document context from which you invoke it.  Let's assume that your document's root element is <lists></lists> and that all the <elementlist></elementlist> are its direct descendants. In this case, 
<xsl:value of select="/lists/elementlist[key='aktif']/value[1]/e" /> will return "KASA".
-- 
Charles Knell
cknell@xxxxxxxxxx - email



-----Original Message-----
From:     Osman Ginar Eren <Cinar.Eren@xxxxxxxxxxxxx>
Sent:     Thu, 4 Nov 2004 18:27:29 +0200
To:       <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Subject:  [xsl] a question

hi,

i am a newbie on this list. i work with FOP and i must prepare an XSL file for my XML file. My XML file contains two elements with different keys, i.e.:

 <elementlist xsi:type="java:org.exolab.castor.mapping.MapItem">
  <key xsi:type="java:java.lang.String">aktif</key> 
 <value xsi:type="java:com.oreilly.hh.QueryTestXML$XMLDovizElement">
  <a>17100</a> 
  <b>746.00</b> 
  <c>010</c> 
  <d>17130900000.00</d> 
  <e>KASA</e> 
  <f>74854930157246.00</f> 
  <g>1</g> 
  <h>1</h> 
  </value>
     <value>
    .
    .
    .
    </value>