RE: [xsl] a sorting conundrum

Subject: RE: [xsl] a sorting conundrum
From: "McNally, David" <David.McNally@xxxxxxxxxx>
Date: Thu, 3 Mar 2005 12:10:14 -0500
I think this should work in XSLT 1.0:

<xsl:sort select="concat(substring-after(concat(normalize-space(.),' '),'
'),normalize-space(.))" />

David McNally                      Moody's Investors Service
Senior Software Engineer           99 Church St, NY NY 10007
David.McNally@xxxxxxxxxx                        212-553-7475

> -----Original Message-----
> From: John Fitzgibbon [mailto:jfitzgibbon@xxxxxxxxxxxxxxxx]
> Sent: Thursday, March 03, 2005 10:32 AM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] a sorting conundrum
> Hi,
> I am attempting to sort an a list of personal names. All of
> the names consist of either a first name followed by a last
> name or of a last name only (there are no middle names). Both
> parts of the name, when present, are enclosed within the one
> tag (span) which has a class='person' attribute, the same tag
> is used to enclose a last name only. I am attempting to sort
> by last name like so
> <xsl:for-each select="html/body//span[@class='person']">
> <xsl:sort select="substring-after(., ' ')"/>
> <xsl:sort select="."/>
> <xsl:sort select="substring-before(., ' ')"/>
> The problem is that names consisting of a last name only
> appear first in my alphabetical sequence and are sorted;
> these are followed by names with a first name and a last name
> and these are also sorted. I require one alphabetical list
> rather than two.
> Can this be done in one fell swoop, without having to write
> an XSL style sheet for the file consisting of two
> alphabetical sequences?
> Any suggestions would be most welcome.
> Regards
> John
> John Fitzgibbon
> Galway Public Library
> Island House
> Cathedral Square
> Galway
> Ireland
> p: 00 353 91 562471
> f: 00 353 91 565039
> w:
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