Subject: RE: [xsl] Testing 2 XML documents for equality - a solution From: Mukul Gandhi <mukul_gandhi@xxxxxxxxx> Date: Wed, 30 Mar 2005 09:10:16 -0800 (PST) |
Thanks a lot Mike for your observations.. I propose this code to solve the attribute ordering problem you cited (for both the documents). <xsl:for-each select="$doc1//@*"> <xsl:sort select="." /> i.e. adding a xsl:sort instruction in the for-each loop. This shall solve this problem! At the very start I said my stylesheet is catering *strictly to XSLT 1.0* ! I am aware that XSLT 2.0 provides many new features which will help in better ways to solve this problem. I'll surely look at the deep-equals() spec in XSLT 2.0 , and the Canonical XML definition.. In fact I took a cursory look at the Canonical XML spec sometime back. *I feel my stylesheet caters to a large subset of Canonical XML definition (I guess about 70-90%). Can you please comment on my this claim? * Also thanks for your other ideas.. Regards, Mukul --- Michael Kay <mike@xxxxxxxxxxxx> wrote: > First you need to specify what you mean by equality. > This is a difficult > question. You could look to the spec of > deep-equals() in XSLT 2.0 for > guidance, or to the Canonical XML definition. > There's scope for endless > debate concerning issues such as comments, > whitespace, namespace prefixes, > unused namespace declarations, and so on. > > Your stylesheet will treat > > <a x="1" y="2"/> > > and > > <a y="2" x="1"/> > > as being not equal, which is definitely wrong. > > Algorithms based on concatenating the contents of > both documents and then > comparing them as strings are likely to have the > possibility of returning a > false equality. > > An algorithm that uses recursive descent of both > trees is likely to be much > faster in the case where the trees aren't equal. > > Michael Kay > http://www.saxonica.com/ __________________________________ Do you Yahoo!? Yahoo! Small Business - Try our new resources site! http://smallbusiness.yahoo.com/resources/
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