Re: [xsl] Can a named template return a node list?

[Dan <dan@xxxxxxxxxxxxxxxx>]

Hi John.

I think what you want to do is this:

  <xsl:variable name="somenode" select="/root/node1"/>

What you were doing is creating a copy of the node (to the output tree)
and then trying to process that copy, which means trying to process the
output. I can't cite a specific rule against that, but I don't think
it's legal. Perhaps someone else on the list can enlighten us.

-- 
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