RE: [xsl] only display if subnodes occur more than once

[Wendell Piez <wapiez@xxxxxxxxxxxxxxxx>]

Aron,

Thanks.

Of course the solution I posted doesn't work either, due to limitations of 
XPath 1.0 and the fact that current() refers not to any node being 
predicated, but to the current node (the node matched).

Quite an interesting problem, actually. It should be pretty straightforward 
in XPath 2.0, but the only XSLT 1.0 solutions I've thought of are very ugly 
and un-XSLTish. That may be unavoidable, again due to limitations in XPath 
1.0 -- but before posting one of those I thought I'd give time to see if 
others can work it out more elegantly....

Anyone?

Oh heck, here's an ugly solution:

<xsl:template match="root/*">
  <xsl:variable name="include">
    <xsl:call-template name="include"/>
  </xsl:variable>
  <xsl:if test="string($include)">
    <xsl:copy-of select="."/>
  </xsl:if>
</xsl:template>

<xsl:template name="include">
  <xsl:for-each select="*">
    <xsl:if test="following-sibling::*[name()=name(current())]">X</xsl:if>
  </xsl:for-each>
</xsl:template>

It uses a template to fake a function, which returns a null value (which 
fails the string() test) if there are no children that have following 
siblings of the same name.

Cheers,
Wendell

At 03:35 PM 7/5/2005, you wrote:
>   The original problem asked (I think), given:
>
> > > <root>
> > >         <sub_a>
> > >                 <elem_1/>
> > >                 <elem_2/>
> > >                 <elem_3/>
> > >         </sub_a>
> > >         <sub_b>
> > >                 <elem_1/>
> > >                 <elem_2/>
> > >                 <elem_2/>
> > >                 <elem_2/>
> > >                 <elem_3/>
> > >         </sub_b>
> > >         <sub_c>
> > >                 <elem_1/>
> > >                 <elem_2/>
> > >                 <elem_3/>
> > >         </sub_c>
> > > </root>
>
> output:
>
> > > <root>
> > >         <sub_b>
> > >                 <elem_2/>
> > >                 <elem_2/>
> > >                 <elem_2/>
> > >         </sub_b>
> > > </root>
>
> Namely, output those sub_* which have more than 1 elem_* children named 
> the same; also output the elem_* children.
>
> --A




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Wendell Piez                            mailto:wapiez@xxxxxxxxxxxxxxxx
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