Subject: [xsl] How to convert day-of-month with xslt 2.0 From: Manfred Staudinger <manfred.staudinger@xxxxxxxxx> Date: Tue, 23 Aug 2005 11:22:39 +0200 |
Hi list, I've done this with xslt 1.0 (awfull, but works), but with all the possibilities of 2.0 I'm a bit lost how to do this: input output 6 06 16 16 (2) 02 (23) 23 otherwise 00 Manfred
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