Subject: Re: [xsl] How to convert day-of-month with xslt 2.0 From: andrew welch <andrew.j.welch@xxxxxxxxx> Date: Tue, 23 Aug 2005 10:48:06 +0100 |
> I've done this with xslt 1.0 (awfull, but works), but with > all the possibilities of 2.0 I'm a bit lost how to do this: > > input output > 6 06 > 16 16 > (2) 02 > (23) 23 > otherwise 00 Couldn't you use translate and format-number in a choose/when? eg: select="format-number(translate(input,'()',''),'00')" I suppose you could replace the choose/when with 2.0's if-then-else, but otherwise 1.0 isn't too verbose. cheers andrew
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