Subject: [xsl] document-uri gives empty sequence From: Manfred Staudinger <manfred.staudinger@xxxxxxxxx> Date: Mon, 7 Nov 2005 05:05:10 -0800 |
Hi list, I've troubles to get document-uri function working in Saxon 8.6, even though I had it working in Saxon 8.5.1. The example in Michael Kay's book "XPath 2.0" is very similar to the test case here (p.333, 3rd line should read '<p><a href="{document-uri(.)}">' ): <?xml version="1.0" encoding="UTF-8" ?> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" indent="yes"/> <xsl:template match="/"> <doc> <xsl:for-each select="collection('Namen?select=*.xml')"> <reg> <h1><xsl:value-of select="body/h3"/></h1> <uri><xsl:value-of select="document-uri(.)"/></uri> </reg> </xsl:for-each> </doc> </xsl:template> </xsl:stylesheet> With only 1 file in the input folder <?xml version="1.0" encoding="UTF-8"?> <body> <h3>Dr. Johann Ruprecht Hegenm|ller</h3> </body> I get this output - but no uri: <?xml version="1.0" encoding="UTF-8"?> <doc> <reg> <h1>Dr. Johann Ruprecht Hegenm|ller</h1> <uri/> </reg> </doc> What I'm missing? Regards, Manfred Staudinger, Vienna
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