Re: [xsl] How to process a list of files

[Ragulf Pickaxe <ragulf.pickaxe@xxxxxxxxx>]

Hi,

I am not quite sure what you mean.
I do not know the processor used in the example, but from what you
ask, and from the example shown, it would seem that you would be able
to use href="{$filename}" where $filename is the full name of the
output document that you want.

Other processors may have different syntax.

Ragulf Pickaxe :-)