Subject: Re: [xsl] finding lowest level in ancestor:: axis From: David Carlisle <davidc@xxxxxxxxx> Date: Thu, 26 Jan 2006 22:44:46 GMT |
> <xsl:variable name="parent" > select="id(@idref)/ancestor::div10 | Thi selects a node set of all the relevant elements. As the name "set" implies node sets are unordered, so it makes no difference how you arrange the terms with | . | is set union and a | b is the same as b | a. However generate-id() takes a single node and returns its id so if you give it a node set, as with most xslt1 functions, it sorts the nodes into document order and uses the 1st node,silently discarding the rest. I think you want $parent to be the nearest ancestor of the idrefed node whose name starts with div so that's select="id(@idref)/ancestor-of-self::*[starts-with(local-name(),'div')][1]" David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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