Subject: Re: [xsl] finding lowest level in ancestor:: axis From: David Carlisle <davidc@xxxxxxxxx> Date: Thu, 26 Jan 2006 23:35:58 GMT |
> The variable was not getting a node-set with the original syntax. was so:-) > When I switched the design to use the choose statement, this resulted in a No to use an xsl:choose you must have used xsl:variable with xsl:choose as content rather than a select expression. Such an xsl:variable never generates a node set in xslt1: it generates a result tree fragment (which would generate an error if passed to generate-id, or any other function expecting a node set). > So based upon that I would say the original design returned something > like I expected but in the reverse order of what I expected, No, it returned a node set, and sets do not have an order (that's why they are called sets not lists or sequences) David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] finding lowest level in a, Dan Vint | Thread | Re: [xsl] finding lowest level in a, Dan Vint |
Re: [xsl] Shallow copy and base URI, David Carlisle | Date | Re: [xsl] Variable number of argume, Dimitre Novatchev |
Month |