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Subject: Re: [xsl] constructing a "variable" select argument From: Florent Georges <darkman_spam@xxxxxxxx> Date: Mon, 27 Feb 2006 20:29:55 +0100 (CET)  | 
Tracey Zellmann wrote:
> However, this does not:
> after calling the template with
> <xsl:with-param name="track" select="T1"/>
  You're selecting here element nodes that are childs of the context
node and whose name is 'T1'.  But I wonder if you don't want the string
'T1' instead:
    <xsl:with-param name="track" select="'T1'"/>
(note the additional quotes).
  Regards,
--drkm
	
	
		
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