Re: [xsl] constructing a "variable" select argument

["Tracey Zellmann" <tracey.zellmann@xxxxxxxxxxx>]

Yes!!

Thank you, Florent and MK.
This will probably simplify my stylesheet by at least a factor of 10.
It is a gotcha.

There is one remaining wrinkle I could use you help with.

I have this statement:
<xsl:copy-of select="/Report/TrackT1/Position[@position='Left 
Front']/MCHistogram[@id='1']/svg:svg"/>

The position and id attributes can change, and I can handle that as in the 
earlier case.

However, the TrackT1 part of the expression can also change - to TrackT2, 
TrackT3, Track5-18, etc, taking on various values.

Assuming I bring a parameter into the template, and possibly use 
concatenation functions, how can I establish the right value in the middle 
of the XPath expression?

----- Original Message ----- 
From: "Florent Georges" <darkman_spam@xxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Monday, February 27, 2006 2:29 PM
Subject: Re: [xsl] constructing a "variable" select argument


> Tracey Zellmann wrote:
>
> > However, this does not:
> > after calling the template with
> > <xsl:with-param name="track" select="T1"/>
>
>  You're selecting here element nodes that are childs of the context
> node and whose name is 'T1'.  But I wonder if you don't want the string
> 'T1' instead:
>
>    <xsl:with-param name="track" select="'T1'"/>
>
> (note the additional quotes).
>
>  Regards,
>
> --drkm
>
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