[xsl] xsl:sort in reverse doc order

[Aditya <adi285@xxxxxxxxx>]

I have an xml file which has the following representation from which i need
to extract user information in reverse documentation order -

<cc>
 <mods>
   <mod>
     <usr>usr1</usr>
      .......
   </mod>
   <mod>
     <usr>usr2</usr>
      .......
   </mod>
   <mod>
     <usr>usr3</usr>
      .......
   </mod>
 </mods>
</cc>

My output should look like

usr3
usr2
usr1

I used the following snippet of code but it doesnt seem to work as expected=
.


<xsl:template match=3D"/cc/mods">
   <xsl:for-each select=3D"mod/usr">
       <xsl:sort select=3D"position()" order=3D"descending" data-type=3D"t=
ext"/>
       <xsl:value-of select=3D"."/>
<xsl:text>
</xsl:text>
   </xsl:for-each>
</xsl:template>

Please let me know what i am doing wrong.

Thanks,

--
Aditya

"Vision is not enough; it must be combined with venture. It is not
enough to stare up the steps; we must step up the stairs." - Vaclav
Havel