Re: [xsl] xsl:sort in reverse doc order

["G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>]

At 2006-03-03 15:53 -0800, Aditya wrote:
> My output should look like
>
> usr3
> usr2
> usr1
>
> I used the following snippet of code but it doesnt seem to work as expected.

Your code worked for me (transcript below).

But note that it is wrong for a larger data-set and the data-type should be:

  data-type="number"

in order to work properly for larger data sets.

But for your data-set, your code works just fine.

I hope this helps.

. . . . . . . . . Ken


T:\ftemp>type aditya.xml
<cc>
 <mods>
   <mod>
     <usr>usr1</usr>
      .......
   </mod>
   <mod>
     <usr>usr2</usr>
      .......
   </mod>
   <mod>
     <usr>usr3</usr>
      .......
   </mod>
 </mods>
</cc>

T:\ftemp>type aditya.xsl
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
                version="1.0">

<xsl:output method="text"/>

<xsl:template match="/">
  <xsl:apply-templates select="/cc/mods"/>
</xsl:template>

<xsl:template match="/cc/mods">
   <xsl:for-each select="mod/usr">
       <xsl:sort select="position()" order="descending" data-type="text"/>
       <xsl:value-of select="."/>
       <xsl:text>
</xsl:text>
   </xsl:for-each>
</xsl:template>

</xsl:stylesheet>
T:\ftemp>xslt aditya.xml aditya.xsl con
usr3
usr2
usr1

T:\ftemp>

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