Subject: Re: [xsl] Re: Keeping a running total? From: Andrew Franz <afranz0@xxxxxxxxxxxxxxxx> Date: Tue, 18 Jul 2006 09:02:30 +1000 |
> So, how many times will parameter shift be required?
Parameter shift will occur whenever a factory's capacity is used up (Fn times)
So we have Fn shifts of parameters. Every shift of parameters takes O(Qn) -because every parameter takes the velue of the next parameter.
Therefore, the time only the shift of parameters will require will be Fn * O(Qn)
which, of course can be written as:
O(Fn) * O(Qn).
This was my initial estimation and you now confirm it.
A better time complexity can be achieved if the "shift parameters" operation can be replaced with something else.
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