Subject: [xsl] Why no namespace node KindTest? From: Florent Georges <darkman_spam@xxxxxxxx> Date: Sat, 26 Aug 2006 22:07:18 +0200 (CEST) |
Hi I wonder why there is no KindTest for namepace nodes. In particular, we can't write something like: if ( $arg instance of namespace() ) ... Of course, as this is the only kind of node that doesn't have a KindTest, it is possible to rewrite it as: if ( $arg instance of namespace() ) ... if ( $item instance of node() and not($item instance of attribute() or $item instance of comment() or $item instance of document-node() or $item instance of element() or $item instance of processing-instruction() or $item instance of text() ) ) ... But it is not as clear as it could be, IMHO. I guess there are only a few need for such a test, but I actually need it in a development (not really, since I have a switch/case on each node kind, so it is just the default branch). I just wonder why such an asymmetrical choice was made by the WG. Regards, --drkm p5.vert.ukl.yahoo.com uncompressed/chunked Sat Aug 26 19:13:38 GMT 2006 ___________________________________________________________________________ Dicouvrez un nouveau moyen de poser toutes vos questions quelque soit le sujet ! Yahoo! Questions/Riponses pour partager vos connaissances, vos opinions et vos expiriences. http://fr.answers.yahoo.com
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