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Re: [xsl] XPath MOD 10 calculation

Subject: Re: [xsl] XPath MOD 10 calculation
From: David Carlisle <davidc@xxxxxxxxx>
Date: Fri, 25 May 2007 10:21:52 +0100
> 10 - ((sum($odd) * 3) + sum($even)) mod 10

yes, or

-sum((-10,$odd,$odd,$odd,$even)) mod 10

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