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Re: [xsl] XPath MOD 10 calculation

Subject: Re: [xsl] XPath MOD 10 calculation
From: "Andrew Welch" <andrew.j.welch@xxxxxxxxx>
Date: Fri, 25 May 2007 10:29:05 +0100
On 5/25/07, David Carlisle <davidc@xxxxxxxxx> wrote:


> 10 - ((sum($odd) * 3) + sum($even)) mod 10

yes, or

-sum((-10,$odd,$odd,$odd,$even)) mod 10 

:) I think you've just turned off Simplification Street and gone down
Obfuscation Road....

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