Re: [xsl] Getting a list of node Text()

Subject: Re: [xsl] Getting a list of node Text()
From: Nicholas Orr <nick@xxxxxxxxxxx>
Date: Wed, 20 Jun 2007 09:05:40 +1000
On 20/06/2007, at 8:51 AM, Houghton,Andrew wrote:

-----Original Message-----
From: Nicholas Orr [mailto:nick@xxxxxxxxxxx]

Essentially I'm trying to get a <Calculation> node which will
be a child node of the current one.  But the issue is that
there will sometimes be one calculation node, and sometimes
multiple nodes.  And
they're not always just child nodes, they might be sub child nodes.
So I might have for my path :




I think you are over thinking the problem. If all you want is the text from all the elements named Calculation then you should be able to do:


Thanks, but in my testing this only returns the first Calculation node, not all of them. I need all of them in a return separated list...


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