Subject: Re: Getting a longest node From: Wendell Piez <wapiez@xxxxxxxxxxxxxxxx> Date: Mon, 17 Jan 2000 12:03:53 +0000 |
Sebastian and all-- At 04:27 PM 1/17/00 +0000, you wrote: >I did something like this; put all the values into a RTF, >convert it to a node-set, sort it numerically, and find the >last one. I append my (uncommented) code which attempts to work out >column widths for a table by adding together all the cell lengths in >each column and working out proportions That's pretty cool, I'll try it. Am I going to need the extension function to get access to the value? That could trouble the purist (or portability freak). > <xsl:value-of select="sum(xt:node-set($cells)/cell)"/> Heh. Still puzzling-- Wendell ====================================================================== Wendell Piez mailto:wapiez@xxxxxxxxxxxxxxxx Mulberry Technologies, Inc. http://www.mulberrytech.com 17 West Jefferson Street Direct Phone: 301/315-9635 Suite 207 Phone: 301/315-9631 Rockville, MD 20850 Fax: 301/315-8285 ---------------------------------------------------------------------- Mulberry Technologies: A Consultancy Specializing in SGML and XML ====================================================================== XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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