Re: [xsl] re-ordering nodes

Subject: Re: [xsl] re-ordering nodes
From: Jeni Tennison <jeni@xxxxxxxxxxxxxxxx>
Date: Wed, 19 Dec 2001 11:02:36 +0000
Hello Srini,

> The goal is to re-group all the <o> nodes at the first level from
> the root node. The relative order is not so much of a concern at
> this time.

You can select all the o elements in your source document, at whatever
level, with:

  //o

You can copy all of them with:

  <xsl:copy-of select="//o" />

So possibly you want something like:

<xsl:template match="list">
  <list>
    <xsl:copy-of select="//o" />
  </list>
</xsl:template>

If you wanted to change the content of the o elements, you should
apply templates to them instead:

  <xsl:apply-templates select="//o" />

And have the template work out what to do with them.

Cheers,

Jeni

---
Jeni Tennison
http://www.jenitennison.com/


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