RE: [xsl] Dynamical work with child nodes

[Roland Juergens <roland_juergens@xxxxxxxxxxxx>]

Thanks a lot. That was exactly what I wanted (and it works, too).

-----Original Message-----
From: Mukul Gandhi [mailto:mukulgandhi2003@xxxxxxxxxxx]
Sent: Dienstag, 6. April 2004 17:49
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] Dynamical work with child nodes


Hi Roland,
  Something like the following might be ok. The
structure just illustrates the concept.

<xsl:template match="/">
   <xsl:for-each select="root/rowset/row">
     <xsl:for-each select="*">
        <xsl:value-of select="name(.)" /> -
<xsl:value-of select="." />
     </xsl:for-each>
   </xsl:for-each>
</xsl:template>

Regards,
Mukul

 --- Roland Juergens <roland_juergens@xxxxxxxxxxxx>
wrote: > Hi,
> 
> I have an XML file like this which contains results
> from a database query.
> Is there a way to go dynamically through the
> subelements of my "row"
> elements, because I want to use it for different
> queries.
> So the subelements like "id" or "name" might change.
> 
> <root>
> 	<rowset>
> 		<row>
> 			<id>1</id>
> 			<name>bla</name>
> 		</row>
> 		<row>
> 			<id>2</id>
> 			<name>blabla</name>
> 		</row>
> 
> 		...(more <row> elements)...
> 
> 	</rowset>
> </root>
> 
> 
> This is how the xsl-file looks like now
> 
> ...
> <xsl:for-each select="root/rowset/row">
> ...
> 	<xsl:value-of select="id"/>
> ...
> 	<xsl:value-of select="name"/>
> ...
> </xsl:for-each>
> ...
> 
> 
> 
> What I imagine is the following :
> I want to get the number of subelements of a "row"
> element, then iterate
> over it to get the names, and then building it
> dynamical.
> Is something like that possible ?
> 
> 
> Roland Juergens
>  

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