Subject: Re: [xsl] xalan and replace "regex" From: Abel Braaksma <abel.online@xxxxxxxxx> Date: Fri, 28 Dec 2007 09:19:44 +0100 |
Matthew, I have checked this and when it nothing worked for me, I decided to post to this list.
A simple sheet to test how would replace work :
<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xalan="http://xml.apache.org/xalan" xmlns:str="http://exslt.org/strings">
<xsl:import href="str/str.xsl" />
<xsl:template match="program"> <xsl:call-template name="str:replace"> <xsl:with-param name="string" select="." /> <xsl:with-param name="search" select="public" /> <xsl:with-param name="replace" select="object" /> </xsl:call-template> </xsl:template>
</xsl:stylesheet>
This did not help and nothing changed in the output. This is why I am considering another solution.
Cheers, -- Abel Braaksma
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