Subject: Re: [xsl] XSL/XPath to generate a list of ancestors? From: Martin Honnen <Martin.Honnen@xxxxxx> Date: Mon, 12 May 2008 19:05:51 +0200 |
I tried this:
<xsl:template match="*" name="fullNameWorker" mode="fullName"> <xsl:if test="generate-id(.)!=generate-id(/)">
You have a template for element nodes (match="*") so why do you test generate-id(.) != generate-id(/) ? An element (.) is never a root node (/).
Martin Honnen http://JavaScript.FAQTs.com/
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