[xsl] Display link text as a hyperlink

[Brent Solly <ultra@xxxxxxxxx>]

Date: Wed, 6 Aug 2008 16:04:28 +0100
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
From: "Andrew Welch" <andrew.j.welch@xxxxxxxxx>
Subject: Re: [xsl] Display link text as a hyperlink
Message-ID: <74a894af0808060804w7b8319a6h8c4f3934c6f60353@xxxxxxxxxxxxxx>

whoooaaaaah there.... you've set off down the wrong road (like so many
others) and it will only end in tears and resentment.  It's completely
the wrong apporach.

To do a search and replace on a string use either replace() or
xsl:analyze-string:

<xsl:analyze-string select="." regex="$the-regex">
  <xsl:matching-substring>
    <a href="http://{.}";>http://<xsl:value-of select="."/></a>
  </xsl:matching-substring>
  <xsl:non-matching-substring>
    <xsl:value-of select="."/>
  </
</

-- 
Andrew Welch
http://andrewjwelch.com
Kernow: http://kernowforsaxon.sf.net/

I'm not sure if your code works in XSLT 1.0.  It doesn't appear to work in XSLT 1.0.  Currently looking into upgrading to XSLT 2.0.