Re: [xsl] copy of specific elements

[Florent Georges <lists@xxxxxxxxxxxx>]

henry human wrote:

> Here is the sample. 

  You still don't show the associated output.  I guess your problem is
like the following.  From:

    <root>
       <e type="author" id="a1"/>
       <e type="author" id="a2"/>
       <e type="author" id="a3"/>
       <e type="section" id="s1"/>
       <e type="section" id="s1"/>
    </root>

you want to walk through the first two e[@type eq 'author'] (because
there are two e[@type ew 'section']).  You can try the following:

    <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
                    version="2.0">

       <xsl:output indent="yes"/>

       <xsl:template match="/">
          <results>
             <xsl:variable name="count" select="
                 count(root/e[@type eq 'section'])"/>
             <xsl:apply-templates select="
                 root/e[@type eq 'author'][position() le $count]"/>
          </results>
       </xsl:template>

       <xsl:template match="e">
          <xsl:element name="{ @id }"/>
       </xsl:template>

    </xsl:stylesheet>

  The output is:

    $ saxon hhuman.xml hhuman.xsl
    <?xml version="1.0" encoding="UTF-8"?>
    <results>
       <a1/>
       <a2/>
    </results>

  If the e elements are not all child of the same parent element, use
parenthesis, in order to have the correct position(), like for instance
in:

    (root//e[@type eq 'author'])[position() le $count]

  Regards,

--drkm






















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