Subject: Re: [xsl] generating xml from xslt From: Martin Honnen <Martin.Honnen@xxxxxx> Date: Tue, 26 Aug 2008 17:59:07 +0200 |
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml"/>
<xsl:template match="@*|node()"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:template>
<xsl:template match="/root/status/locn/loc1/address"> <xsl:element name="add1"></xsl:element> <xsl:element name="add2"></xsl:element> <xsl:element name="add3"></xsl:element> </xsl:template>
and add three templates <xsl:template match="add1"> <xsl:copy> <xsl:value-of select="$a1"/> </xsl:copy> </xsl:template> <xsl:template match="add2"> <xsl:copy> <xsl:value-of select="$a2"/> </xsl:copy> </xsl:template> <xsl:template match="add3"> <xsl:copy> <xsl:value-of select="$a3"/> </xsl:copy> </xsl:template> --
Martin Honnen http://JavaScript.FAQTs.com/
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