Subject: [xsl] Select a node only if its previous siblings have specific attributes From: Philipp Kursawe <phil.kursawe@xxxxxxxxx> Date: Fri, 15 Apr 2011 19:40:14 +0200 |
Hello, a node with @result='9' should be select if one of its previous siblings has @result=10 or @result=11. Only the most recent node with @result=9 should be selected. given the following examples: <root> <data result="11"/> <data result="10"/> <data result="9"/> </root> Should select data[3] <root> <data result="11"/> <data result="5"/> <data result="9"/> </root> Should not select any node, because one of data[3] prev siblings has @result != 10|11 <root> <data result="11"/> <data result="9"/> <data result="5"/> <data result="9"/> </root> Should select data[2] not data[4] because data[4] has previous siblings with @result != 10|11 How would the XPath selector look like? Basically i need to find the first() (or last()?) node whose previous siblings do not have @result=10|11 Thanks for your help! Phil
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