Subject: Re: [xsl] Select a node only if its previous siblings have specific attributes From: Brandon Ibach <brandon.ibach@xxxxxxxxxxxxxxxxxxx> Date: Fri, 15 Apr 2011 14:44:28 -0400 |
I'm not sure I'm completely clear on your requirement, but try this: //data[@result = '9'][not(preceding-sibling::data[@result != '10' and @result != '11'])][last()] -Brandon :) On Fri, Apr 15, 2011 at 1:40 PM, Philipp Kursawe <phil.kursawe@xxxxxxxxx> wrote: > Hello, > > a node with @result='9' should be select if one of its previous > siblings has @result=10 or @result=11. Only the most recent node with > @result=9 should be selected. > > given the following examples: > > <root> > <data result="11"/> > <data result="10"/> > <data result="9"/> > </root> > Should select data[3] > > <root> > <data result="11"/> > <data result="5"/> > <data result="9"/> > </root> > Should not select any node, because one of data[3] prev siblings has > @result != 10|11 > > <root> > <data result="11"/> > <data result="9"/> > <data result="5"/> > <data result="9"/> > </root> > Should select data[2] not data[4] because data[4] has previous > siblings with @result != 10|11 > > How would the XPath selector look like? Basically i need to find the > first() (or last()?) node whose previous siblings do not have > @result=10|11 > > Thanks for your help! > Phil
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