Re: [xsl] Select a node only if its previous siblings have specific attributes

[Philipp Kursawe <phil.kursawe@xxxxxxxxx>]

Works like a charme Brandon! Thanks!

On Fri, Apr 15, 2011 at 8:44 PM, Brandon Ibach
<brandon.ibach@xxxxxxxxxxxxxxxxxxx> wrote:
> I'm not sure I'm completely clear on your requirement, but try this:
>
> //data[@result = '9'][not(preceding-sibling::data[@result != '10' and
> @result != '11'])][last()]
>
> -Brandon :)
>
>
> On Fri, Apr 15, 2011 at 1:40 PM, Philipp Kursawe <phil.kursawe@xxxxxxxxx>
wrote:
>> Hello,
>>
>> a node with @result='9' should be select if one of its previous
>> siblings has @result=10 or @result=11. Only the most recent node with
>> @result=9 should be selected.
>>
>> given the following examples:
>>
>> <root>
>> <data result="11"/>
>> <data result="10"/>
>> <data result="9"/>
>> </root>
>> Should select data[3]
>>
>> <root>
>> <data result="11"/>
>> <data result="5"/>
>> <data result="9"/>
>> </root>
>> Should not select any node, because one of data[3] prev siblings has
>> @result != 10|11
>>
>> <root>
>> <data result="11"/>
>> <data result="9"/>
>> <data result="5"/>
>> <data result="9"/>
>> </root>
>> Should select data[2] not data[4] because data[4] has previous
>> siblings with @result != 10|11
>>
>> How would the XPath selector look like? Basically i need to find the
>> first() (or last()?) node whose previous siblings do not have
>> @result=10|11
>>
>> Thanks for your help!
>> Phil